t^(2/3)+10t^(1/3)+16=0

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Solution for t^(2/3)+10t^(1/3)+16=0 equation:


t in (-oo:+oo)

t^(2/3)+10*t^(1/3)+16 = 0

t_1 = t^(1/3)

1*t_1^2+10*t_1^1+16 = 0

t_1^2+10*t_1+16 = 0

DELTA = 10^2-(1*4*16)

DELTA = 36

DELTA > 0

t_1 = (36^(1/2)-10)/(1*2) or t_1 = (-36^(1/2)-10)/(1*2)

t_1 = -2 or t_1 = -8

t_1 = -8

t^(1/3)+8 = 0

1*t^(1/3) = -8 // : 1

t^(1/3) = -8

( -8 < 0 i 1/3 in (0:1) ) => t naleu017Cy do O

t_1 = -2

t^(1/3)+2 = 0

1*t^(1/3) = -2 // : 1

t^(1/3) = -2

( -2 < 0 i 1/3 in (0:1) ) => t naleu017Cy do O

t belongs to the empty set

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